The Snooker China Open continues on August 10, Beijing time. Today's schedule features four matches, producing four additional round-of-16 qualifiers. Four Chinese players are in action: Chang Bingyu battles Robertson, a top player from the 80s generation, hoping for a surprise victory; Si Jiahui and Jiang Jun engage in an internal duel, guaranteeing one Chinese player in the last 16; Pang Junxu takes on Selby, a four-time world champion, and is expected to lose.

At 14:00, two matches will take place: Chang Bingyu vs. "Australian Cannon" Robertson. Chang, a rising star in Chinese snooker, is known for his talent, sharp accuracy, and frequent century breaks, earning recognition from many snooker legends. However, his weaknesses include inexperience and poor defensive positioning. In the first round of this event, he directly faces Robertson, one of the 80s Five Tigers. Despite the huge gap in achievements, Chang is capable of beating any player on his day, provided his accuracy is on point, and he looks to upset Robertson. At the same time, Si Jiahui and Jiang Jun will play a Chinese derby. Their styles and paces differ, making it a clash of opposites. Since they know each other well, the outcome is highly uncertain.


At 19:30, Kyren Wilson will face Aaron Hill. Wilson, the top player of the post-90s generation, recently reached the final of the Shanghai Masters and is in strong form. Therefore, this match is expected to be one-sided, and Wilson should advance easily. At the same time, Chinese player Pang Junxu will take on Selby. This is a battle of grinders, depending on who plays slower. Given the significant gap in strength, Selby is more likely to win. We look forward to exciting matches!
By Titan Xiaoshuo